Equations which are never true: 5.2 Solve: 5 = 0 This equation has no solution. A a non-zero constant never equals zero. Solving a Single Variable Equation: 5.3 Solve: x-16 = 0 Add 16 to both sides of the equation: x = 16. One solution was found: x = 16. Minus 3/8 becomes plus 3/8 when it moves to other side of equal sign, making8/8 or 1.

• Is 5 8 Greater Than 3 8
• 5 8 Vs 3 4

It can sometimes be difficult to multiply fractions, such as 5/8 times 3/10. But it's no problem! We have displayed the answer below: 5/8 x 3/10 = 3/16 How did we solve the problem above? When we multiply two fractions, such as 5/8 x 3/10, we simply multiply the. Algebra Calculator - get free step-by-step solutions for your algebra math problems.

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How do you solve #1/8x-5=3#?

1 Answer

#x=64# See detailed explanation for how you do it!

Explanation:

Tinyalarm 1 9 7 meters. #color(red)('Change things so that there is only one')##color(red)(x)##color(red)('and it is on the left of the = sign. Everything else is to be on the right of the = sign')#

Brackets use only to show what parts are being changed. The brackets are only for demonstration to you what is happening. They serve no other purpose.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Step1
Move the 5 from left to right

#color(brown)('In add or subtract, if we can change a number to zero'##color(Brown)('it has no effect. This is the same as removing it from that side of the equation.')#

Add 5 to both sides giving
#(1/8x-5) +5 = (3) +5#

Call blizzard support. #1/8x +0 =8# ........(1)

I have used plus 5 because negative 5 and plus 5 make zero.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Is 5 8 Greater Than 3 8

Step 2

Rewrite equation (1) as:

#1/8x = 8# ........(2)

#color(brown)('In this case if we can change the')##color(brown)(1/8)##color(brown)('into 1 we are then multiplying')##color(brown)(x)##color(brown)('by 1. Consequently not changing its value')#

Multiply both sides of equation (2) by 8

#(1/8 x) times 8= (8) times 8#

But #1/8 times 8# is the same as #8/8# which is 1 so now we have changed equation (2) to

#1 times x = 64#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

There you have it: Only #x# on one side and its value on the other.

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